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10. To prepare coffee, water has to be boiled starting from room temperature t_{1} = 15 deg * C Assuming that the electric kettle is 50% efficient, how much does it cost to boil 1 liter if electricity costs 10 ngwe per kWh?
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10. To prepare coffee, water has to be boiled starting from room tempe...
Introduction
To calculate the cost of boiling 1 liter of water from room temperature (15°C) to boiling point (100°C), we need to determine the energy required and then the cost based on electricity rates and kettle efficiency.
Energy Calculation
- Specific Heat Capacity of Water: Approximately 4.186 kJ/kg°C
- Temperature Change:
- Final Temperature: 100°C
- Initial Temperature: 15°C
- ΔT = 100 - 15 = 85°C
- Mass of Water: 1 liter of water = 1 kg
- Energy Required (Q):
- Q = mass * specific heat * ΔT
- Q = 1 kg * 4.186 kJ/kg°C * 85°C = 355.81 kJ
- Convert kJ to kWh:
- 1 kWh = 3,600 kJ
- Energy in kWh = 355.81 kJ / 3,600 kJ/kWh ≈ 0.098 kWh
Kettle Efficiency
- Efficiency of Kettle: 50%
- Actual Energy Consumed:
- Energy required = Energy in kWh / Efficiency
- Energy consumed = 0.098 kWh / 0.50 = 0.196 kWh
Cost Calculation
- Electricity Cost: 10 ngwe per kWh
- Total Cost:
- Cost = Energy consumed * Cost per kWh
- Cost = 0.196 kWh * 10 ngwe/kWh = 1.96 ngwe
Conclusion
- To boil 1 liter of water from room temperature to boiling point using a 50% efficient kettle costs approximately 1.96 ngwe.
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10. To prepare coffee, water has to be boiled starting from room temperature t_{1} = 15 deg * C Assuming that the electric kettle is 50% efficient, how much does it cost to boil 1 liter if electricity costs 10 ngwe per kWh?
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